ICSE Class 10 Chemistry Question 7 of 64

Metallurgy — Question 2

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Question 2

Extraction of Aluminium 
Step 1 : Dressing of the ore chemical method 
Baeyer's process - Step 1, Step 2, Step 3 
14. Bauxite to - sodium aluminateAl2O3.2H2O+NaOH150200°C...............+...............\text{Al}_2\text{O}_3.2\text{H}_2\text{O} + \text{NaOH} \xrightarrow{150-200 \degree\text{C}} ............... + ...............
15. Sodium aluminate to - aluminium hydroxideNaAlO2+H2O5060°C...............+...............\text{NaAlO}_2 + \text{H}_2\text{O} \xrightarrow{50-60 \degree\text{C}} ............... + ............... \downarrow
16. Aluminium hydroxide to pure aluminaAl(OH)31100°C...............+...............\text{Al(OH)}_3 \xrightarrow{1100 \degree\text{C}} ............... + ...............
Step 2: Conversion of conc. ore to its oxide   
Step not necessary since the ore is already an oxide   
Step 3: Reduction of metallic oxide to its metal   
Hall Heroult's Process - Reduction by electrolysis   
17. Electrolytic reduction of pure aluminaAl2O3 ⇌ ............... + ...............
18. At cathode2Al3+ + 6e- ⟶ ...............
19. At anode3O2- - 6e- ⟶ 3[...............] ⟶ 3O2
Step 4: Electrorefining of aluminium [reference] 
Answer
Extraction of Aluminium 
Step 1 : Dressing of the ore chemical method 
Baeyer's process - Step 1, Step 2, Step 3 
14. Bauxite to - sodium aluminateAl2O3.2H2O+2NaOH150200°C2NaAlO2+3H2O\text{Al}_2\text{O}_3.2\text{H}_2\text{O} + \text{2NaOH} \xrightarrow{150-200 \degree\text{C}} \bold{2NaAlO}_\bold{2} + \bold{3H}_\bold{2}\bold{{O}}
15. Sodium aluminate to - aluminium hydroxideNaAlO2+2H2O5060°CNaOH+Al(OH)3\text{NaAlO}_2 + \text{2H}_2\text{O} \xrightarrow{50-60 \degree\text{C}} \bold{NaOH} + \bold{Al(OH)}_\bold{3}\downarrow
16. Aluminium hydroxide to pure alumina2Al(OH)31100°CAl2O3+3H2O\text{2Al(OH)}_3 \xrightarrow{1100 \degree\text{C}} \bold{Al}_\bold{2}\bold{O}_\bold{3} + \bold{3H}_\bold{2}\bold{{O}}
Step 2: Conversion of conc. ore to its oxide   
Step not necessary since the ore is already an oxide   
Step 3: Reduction of metallic oxide to its metal   
Hall Heroult's Process - Reduction by electrolysis   
17. Electrolytic reduction of - pure aluminaAl2O32Al3+ + 3O2-
18. At cathode2Al3+ + 6e-2Al
19. At anode3O2- - 6e- ⟶ 3[O] ⟶ 3O2
Step 4: Electrorefining of aluminium [reference]