Give one equation each to show the following properties of sulphuric acid:
(a) Dehydrating property
(b) Acidic nature
(c) As a non-volatile acid
(i) CuSO4.5H2O→Conc. H2SO4CuSO4 [White Anhydrous]+5H2O\text{CuSO}_4\text{.5H}_2\text{O} \xrightarrow{\text{Conc. H}_2\text{SO}_4} \text{CuSO}_4 \text{ [White Anhydrous]} + 5\text{H}_2\text{O}CuSO4.5H2OConc. H2SO4CuSO4 [White Anhydrous]+5H2O
(ii) Na2SO3 + H2SO4 (dil.) ⟶ Na2SO4 + H2O + SO2
(iii) NaNO3+H2SO4[conc.]→<200°CNaHSO4+HNO3\text{NaNO}_3 + \text{H}_2\text{SO}_4 [\text{conc.}]\xrightarrow{\lt 200 \degree\text{C}} \text{NaHSO}_\text{4} + \text{HNO}_\bold{3}NaNO3+H2SO4[conc.]<200°CNaHSO4+HNO3
