Given,
At same temperature and pressure Mass of hydrogen = 50 g
Mass of gas X = 200 g
Mass of gas Y = 500 g
V.D. of gas X = mass of equal volume of H2mass of certain volume of gas X = 50200 = 4
V.D. of gas Y = mass of equal volume of H2mass of certain volume of gas Y = 50500 = 10
Molecular weight = 2 x V.D. = 2 x 10 = 20 a.m.u.
∴ The vapour density of gas X is 4 and Molecular mass of gas Y is 20 a.m.u.