ICSE Class 10 Chemistry Question 23 of 37

Mole Concept and Stoichiometry — Question 17

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Question

Question 17

Urea is a very important nitrogenous fertilizer. It's formula is CON2H4. Calculate the percentage of nitrogen in urea. (C = 12, O = 16, N = 14 and H = 1).

Answer

Molar mass of urea (CON2H4) = 12 + 16 + 28 + 4 = 60 g

Molar mass of nitrogen (N2) = 2 x 14 = 28 g

60 g urea has mass of nitrogen = 28 g

∴ 100 g urea will have mass

= 28×10060\dfrac{28 \times 100 }{60}

= 46.67%