Mole Concept and Stoichiometry — Question 6

$\begin{matrix} 2\text{H}_2\text{O} & \longrightarrow 2\text{H}_2 \space + & \text{O}_2 \\ 2(2 + 16) & & 2(16) \\ 36 \text{g} & & 32 \text{g} \\ \end{matrix}$

36 g of water produces 32 g of O₂

∴ 18 g of water will produced

= $\dfrac{32}{36}$ x 18 = 16 g of O₂

$\begin{matrix} 2\text{H}_2\text{O} & \longrightarrow 2\text{H}_2 \space + & \text{O}_2 \\ 2\text{ mole} & & 1\text{ mole} \\ \end{matrix}$

2 moles of water produces 1 mole of oxygen

∴ 1 mole of water will produce $\dfrac{1}{2} \times 1$ = 0.5 moles of O₂

1 mole of O₂ occupies 22.4 L volume

∴ 0.5 moles will occupy = 22.4 × 0.5

= 11.2 L