Mole Concept & Stoichiometry Miscellaneous Exercises — Question 19

(a) According to Avogadro's law : The volume occupied by 1 mole of chlorine is 22.4 dm³

(b) According to Boyle's Law: PV = constant

Hence, if pressure is doubled then volume will become half i.e. $\dfrac{22.4}{2}$ = 11.2 dm³

(c) V₁ = 22.4 dm³

T₁ = 273 K

T₂ = 273 + 273 K = 546 K

V₂ = ?

According to charles law:

$\dfrac{\text{V}_1}{\text{T}_1}$ = $\dfrac{\text{V}_2}{\text{T}_2}$

Substituting to we get,

$\dfrac{ 22.4}{273}$ = $\dfrac{\text{V}_2}{546}$

Hence, V₂ = $\dfrac{ 22.4}{273}$ x 546 = 44.8 dm³

(c) Mass of 1 mole Cl₂ gas = 35.5 × 2 = 71 g