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ICSE Class 10 Chemistry Question 24 of 72

Mole Concept & Stoichiometry Miscellaneous Exercises — Question 24

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Question 23

What mass of copper hydroxide is precipitated by using 200 g of sodium hydroxide?

2NaOH + CuSO4 ⟶ Na2SO4 + Cu(OH)2 ↓

[Cu = 64, Na = 23, S = 32, H = 1]

Answer

2NaOH+CuSO4⟶Na2SO4+Cu(OH)2↓2[23+1664+2[16+1]+1]=64+34=80 g=98g\begin{matrix} 2\text{NaOH} & + & \text{CuSO}_4 & \longrightarrow & \text{Na}_2\text{SO}_4 & + & \text{Cu(OH)}_2\downarrow \\ 2[23 + 16 & & & & & & 64 + 2[16 + 1] \\ + 1] & & & & & & = 64 + 34 \\ = 80 \text{ g} & & & & & & = 98 \text{g} \\ \end{matrix}

80 g of sodium hydroxide precipitates 98 g of copper hydroxide.

∴ 200 g of sodium hydroxide will precipitate 9880\dfrac{98}{80} x 200 = 245 g of copper hydroxide.

Hence, 245 g. of copper hydroxide is precipitated.