ICSE Class 10 Chemistry
Question 28 of 72
Mole Concept & Stoichiometry Miscellaneous Exercises — Question 28
Back to all questionsMolecular mass of Ca(NO3)2
= 40 + [2(14) + 6(16)]
= 40 + 28 + 96
= 164 g
Mass of N2 in Ca(NO3)2 = 28 g
In 1 hectare of soil, 20 kg of N2 is removed
∴ In 10 hectare field N2 removed is 20 x 10 = 200 kg
28 g N2 is present in 164 g of Ca(NO3)2
So, 200 kg or 200,000 g of N2 is present in x 200,000
= 1171428 g = 1171.4 kg