The reaction: 4N2O + CH4 ⟶ CO2 + 2H2O + 4N2 takes place in the gaseous state. If all volumes are measured at the same temperature and pressure, calculate the volume of dinitrogen oxide (N2O) required to give 150 cm3 of steam.
4N2O+CH4⟶CO2+2H2O+4N24 Vol1 Vol1 Vol2 Vol4 Vol\begin{matrix} 4\text{N}_2\text{O} & + &\text{CH}_4 & \longrightarrow & \text{CO}_2 & + & 2\text{H}_2\text{O} & + &4\text{N}_2 \\ 4 \text{ Vol} && 1 \text{ Vol} && 1 \text{ Vol} && 2 \text{ Vol} && 4\text{ Vol} \\ \end{matrix}4N2O4 Vol+CH41 Vol⟶CO21 Vol+2H2O2 Vol+4N24 Vol
2 x 22400 litre steam is produced by 4 × 22400 cm3 N2O
∴ 150 cm3 steam will be produced by
= 4×224002×22400\dfrac{4 × 22400}{2 × 22400}2×224004×22400 x 150 = 300 cc of N2O
