Mole Concept & Stoichiometry Miscellaneous Exercises — Question 41

(a) Molar mass of sulphur dioxide = 32 + 2(16) = 64 g

64 g of sulphur dioxide = 1 mole

So, 3.2 g = $\dfrac{1}{64}$ x 3.2 = 0.05 moles

(b) 1 mole of SO₂ = 6.02 × 10²³ molecules

So, in 0.05 moles, no. of molecules = 6.02 × 10²³ × 0.05 = 3 × 10²²

(c) The volume occupied by 64 g of SO₂ = 22.4 dm³

3.2 g of SO₂ will be occupied by volume

$\dfrac{22.4}{64}$ x 3.2 = 1.12 L