A certain gas 'X' occupies a volume of 100 cm3 at S.T.P. and weighs 0.5 g. Find its relative molecular mass
100 cm3 weighs 0.5 g
∴ 22400 cm3 weighs 0.5100\dfrac{0.5}{100}1000.5 x 22400 = 112 g
Hence, relative molecular mass of the gas = 112 g.
