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ICSE Class 10 Chemistry Question 54 of 72

Mole Concept & Stoichiometry Miscellaneous Exercises — Question 54

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54
Question

Question 48(a-ii)

Calculate the percentage of nitrogen and oxygen in ammonium nitrate. (Relative molecular mass of ammonium nitrate is 80, H = 1, N = 14, O = 16).

Answer

Given,

molecular mass of ammonium nitrate = 80

mass of nitrogen in 1 mole of ammonium nitrate (NH4NO3) is 2(14) = 28 g

percentage of nitrogen in ammonium nitrate = 2880\dfrac{28}{80} x 100 = 35%

mass of oxygen in 1 mole of ammonium nitrate (NH4NO3) is 3(16) = 48 g

percentage of oxygen in ammonium nitrate = 4880\dfrac{48}{80} x 100 = 60%

Hence, percentage of nitrogen is 35% and percentage of oxygen is 60%