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ICSE Class 10 Chemistry Question 6 of 72

Mole Concept & Stoichiometry Miscellaneous Exercises — Question 6

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Question 6

Urea (CO(NH2)2) is an important nitrogenous fertilizer, and is sold in 50 kg sacks. What mass of nitrogen is in one sack of urea?

Answer

Molar mass of urea [CO(NH2)2] = 12 + 16 + 2[14 + (2 x 1)]

= 28 + 2(16)

= 28 + 32

= 60 g

50 kg of urea = 50,000 g of urea

Nitrogen in 60 g of CO(NH2)2 = 2 x 14 = 28 g

∴ Nitrogen in 50,000 g urea = 28×50,00060\dfrac{28 \times 50,000 }{60}

= 23,333 g = 23.3 kg