ICSE Class 10 Chemistry Question 20 of 30

Periodic Table — Periodic Properties & Variation of Properties — Question 28

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Question 28

State the relation between atomic number and atomic mass for light elements. State which elements are considered radioactive giving reasons.

Answer

Electronic configuration of lighter elements shows that the elements which have an even number of proton, for example, atomic numbers like 24He_2^4\text{He}, 612C_6^{12}\text{C} etc., have their mass numbers twice the atomic numbers except for 49Be_4^9\text{Be} and 1840Ar_{18}^{40}\text{Ar}.
Elements which have an odd number of protons like 37Li_3^7\text{Li}, 511B_5^{11}\text{B} etc., have their mass number twice the atomic numbers + 1 (A = 2Z + 1) except 714N_7^{14}\text{N} and 11H_1^1\text{H}

Elements with neutron:proton ratio 1.5 and above are considered as radioactive as the nucleus of such elements becomes unstable causing their radioactive decay. For example, in Uranium (92235U)(_{92}^{235}\text{U}):

No. of protons (p) = 92
No. of neutrons (n) = 235 - 92 = 143

n : p = 14392\dfrac{143}{92} = 1.5543

A neutron:proton ratio greater than 1.5 makes Uranium radioactive.