Question 4(a)The percentage composition of a gas is:Nitrogen 82.35%, Hydrogen 17.64%.Find the empirical formula of the gas. [N = 14, H = 1]

Question

Accepted Answer

Element% compositionAt. wt.Relative no. of atomsSimplest ratioNitrogen82.351482.3514\dfrac{82.35 }{14}1482.35​ = 5.885.885.88\dfrac{5.88}{5.88}5.885.88​ = 1Hydrogen17.64117.641\dfrac{17.64}{1}117.64​ = 17.6417.645.88\dfrac{17.64}{5.88}5.8817.64​ = 3Simplest ratio of whole numbers = N : H = 1 : 3Hence, empirical formula is NH3

Element	% composition	At. wt.	Relative no. of atoms	Simplest ratio
Nitrogen	82.35	14	$\dfrac{82.35 }{14}$ = 5.88	$\dfrac{5.88}{5.88}$ = 1
Hydrogen	17.64	1	$\dfrac{17.64}{1}$ = 17.64	$\dfrac{17.64}{5.88}$ = 3

Solved 2018 Question Paper ICSE Class 10 Chemistry — Question 8

Question 4(a)