A compound X (having vinegar like smell) when treated with ethanol in the presence of the acid Z, gives a compound Y which has a fruity smell.
The reaction is:
C2H5OH+X→ZY+H2O\text{C}_2\text{H}_5\text{OH} + \text{X} \xrightarrow{\text{Z}} \text{Y} + \text{H}_2\text{O}C2H5OH+XZY+H2O
(i) Identify Y and Z.
(ii) Write the structural formula of X.
(iii) Name the above reaction.
C2H5OHethyl alcohol+CH3COOHacetic acid→Conc. H2SO4CH3−COO−C2H5ethyl ethanoate+H2O\underset{\text{ethyl alcohol}}{\text{C}_2\text{H}_5\text{OH}} + \underset{\text{acetic acid}}{\text{CH}_3\text{COOH}} \xrightarrow{\text{Conc. H}_2\text{SO}_4} \underset{\text{ethyl ethanoate}}{\text{CH}_3-\text{COO}-\text{C}_2\text{H}_5} + \text{H}_2\text{O}ethyl alcoholC2H5OH+acetic acidCH3COOHConc. H2SO4ethyl ethanoateCH3−COO−C2H5+H2O
(i) Y is ethyl acetate and Z is conc. sulphuric acid
(ii) Structural formula of X (ethanoic acid) is shown below:
(iii) Esterification reaction
