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ICSE Class 10 Chemistry Question 11 of 18

Solved 2019 Question Paper ICSE Class 10 Chemistry — Question 9

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Question

Question 4(c)

Name the following organic compounds:

(i) The compound with 3 carbon atoms whose functional group is a carboxyl.

(ii) The first homologue whose general formula is CnH2n

(iii) The compound that reacts with acetic acid to form ethyl ethanoate.

(iv) The compound formed by complete chlorination of ethyne.

Answer

(i) Propanoic acid [C3H7CHO]

(ii) Ethene [C2H4]

(iii) Ethyl alcohol

C2H5OHethyl alcohol+CH3COOHacetic acid→Conc. H2SO4CH3−COO−C2H5ethyl ethanoate+H2O\underset{\text{ethyl alcohol}}{\text{C}_2\text{H}_5\text{OH}} + \underset{\text{acetic acid}}{\text{CH}_3\text{COOH}} \xrightarrow{\text{Conc. H}_2\text{SO}_4} \underset{\text{ethyl ethanoate}}{\text{CH}_3-\text{COO}-\text{C}_2\text{H}_5} + \text{H}_2\text{O}

(iv) 1,1,2,2 tetrachloroethane

1,1,2,2 tetrachloroethane. Organic Chemistry, Simplified Chemistry Dalal Solutions ICSE Class 10