ICSE Class 10 Chemistry
Question 12 of 18
Solved 2020 Question Paper ICSE Class 10 Chemistry — Question 12
Back to all questions(i) Gram molecular mass of methane = V.D. x 2 = 8 x 2 = 16 g
16 g of methane occupies 22.4 lit.
∴ 40 g of methane will occupy = x 40 = 56 lits.
(ii) Gram molecular mass of NaOH = 23 + 16 + 1 = 40 g
40 g of NaOH = 1 mole
∴ 160 g of NaOH = = 4 moles.