Solved Sample Paper 2 — Question 9

Percentage of particular element = $\dfrac{\text{Mass}}{\text{Total mass}}$ x 100

C₆H₁₂O₆ = 6(12) + 12(1) + 6(16) = 72 + 12 + 96 = 180 g per mole

Percentage of C = $\dfrac{72}{180}$ x 100 = 40%

Percentage of H = $\dfrac{12}{180}$ x 100 = 6.67%

Percentage of O = $\dfrac{96}{180}$ x 100 = 53.33%

Hence, Percentage of C = 40%, H = 6.67% and O = 53.33%