6
Question Question 4(ii)
An organic compound has an empirical formula (CH2O). Its vapour density is 45. Then what will be the molecular formula of the compound?
Given,
Empirical formula = CH2O
Hence, empirical formula mass = 12 + 2(1) + 16 = 12 + 2 + 16 = 30 g
Molecular weight = 2 x Vapour density = 2 x 45 = 90
Molecular formula = n x empirical formula
where,
n =
∴ n = = 3
Hence, molecular formula = 3 x CH2O = C3H6O3
Therefore, the molecular formula of the compound is C3H6O3