Solved Sample Paper 5 — Question 9

Gram molecular mass of SO₂ = 32 + 2(16) = 32 + 32 = 64 g

64 g of SO₂ occupy 22.4 lit of vol at STP

∴ 320 g of SO₂ will occupy = $\dfrac{22.4}{64}$ x 320 = 112 lit.

Hence, volume of 320 g of SO₂ = 112 lit.

(b) Gram molecular mass of S = 32

6.022 × 10²³ atoms weigh = 32 g

10²² atoms will weigh = $\dfrac{32}{6.022 \times 10^{23}}$ x 10²² = 0.531 g

Hence, the mass of 10²² atoms of sulphur = 0.531 g