ICSE Class 10 Chemistry Question 17 of 53

Study of Compounds — Hydrogen Chloride — Question 4

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Question

Question 4

How will the action of dilute hydrochloric acid enable you to distinguish between the following?

(a) Sodium carbonate and sodium sulphite

(b) Sodium thiosulphate and sodium sulphite.

Answer

(a) When Sodium carbonate is treated with dil. HCl, odourless carbon dioxide gas is produced.

Na2CO3 + 2HCl ⟶ 2NaCl + H2O + CO2

However, when sodium sulphite is treated with dil.HCl, sulphur dioxide gas with a suffocating odour (burning smell) is produced.

Na2SO3 + 2HCl ⟶ 2NaCl + H2O + SO2

(b) When sodium thiosulphate is treated with dil. HCl it produces sulphur dioxide gas and yellow sulphur precipitates.

Na2S2O3 + 2HCl ⟶ 2NaCl + S + H2O + SO2

However, S is not produced when sodium sulphite is treated with dil.HCl.

Na2SO3 + 2HCl ⟶ 2NaCl + H2O + SO2