ICSE Class 10 Chemistry
Question 7 of 62
Study of Compounds — Sulphuric Acid — Question 15
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Question Question 15
Give two tests for dilute sulphuric acid with balanced equations. State why
(i) BaCl2
(ii) Pb(NO3)2
are used for the above tests
(i) BaCl2 solution on treating with dilute sulphuric acid forms white ppt. of barium sulphate, which is insoluble in dilute sulphuric acid.
BaCl2 + H2SO4 (dil) ⟶ 2HCl + BaSO4 ↓ [white ppt. formed]
(ii) Pb(NO3)2 on treating with dilute sulphuric acid gives white ppt of lead sulphate, which is insoluble in dil. H2SO4.
Pb(NO3)2 + H2SO4 (dil) ⟶ 2HNO3 + PbSO4 ↓ [white ppt. formed]
BaCl2 and Pb(NO3)2 are used for the above tests as they react with H2SO4 and form BaSO4 and PbSO4 respectively, which are the only compounds insoluble in dil. sulphuric acid.