Study of Compounds — Sulphuric Acid — Question 58
Back to all questionsQuestion 2(2019)
Distinguish between the following pairs of compounds using the reagent given in the bracket:
Dilute hydrochloric acid and dilute sulphuric acid [using lead nitrate soln.]
Sulphuric acid forms a white precipitate with lead nitrate solution. This precipitate does not dissolve on warming the reaction mixture.
H2SO4 (dil.) + Pb(NO3)2 ⟶ 2HNO3 + PbSO4 ↓ [white ppt. formed which does not dissolve on warming the mixture].
Hydrochloric acid forms a white precipitate with lead nitrate solution. This precipitate dissolves on warming the reaction mixture so as to form clear solution.
2HCl (dil.) + Pb(NO3)2 ⟶ 2HNO3 + PbCl2 ↓ [white ppt. formed which dissolves on warming the mixture].
Hence, dilute hydrochloric acid and dilute sulphuric acid can be distinguished using lead nitrate solution.