ICSE Class 10 Computer Applications Question 24 of 76

Revising Basic Java Concepts — Question 28

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28
Question

Question 14(l)

State the value and type of each expression.

Math.pow(4, -2)
Answer

The output value is 0.0625. The type of expression is double.

Explanation

Math.pow(x, y) returns x raised to the power of y as a double value. Math.pow(4, -2) is equivalent to 4-2 i.e., 142\dfrac{1}{4^2} = 0.0625. Hence, output is 0.0625 and data type of result is double.