Question 1

Question 1(i)A mechanism where one class acquires the properties of another class:PolymorphismInheritanceEncapsulationAbstraction

Accepted Answer

InheritanceReason — Inheritance enables new classes to receive or inherit the properties and methods of existing classes.

Question 2

Question 1(ii)Identify the type of operator &&:ternaryunarylogicalrelational

Accepted Answer

logicalReason — Logical operators operate only on boolean operands and are used to construct complex decision-making expressions. Logical AND && operator evaluates to true only if both of its operands are true.

Question 3

Question 1(iii)The Scanner class method used to accept words with space:next()nextLine()Next()nextString()

Accepted Answer

nextLine()Reason — nextLine() reads the input till the end of line so it can read a full sentence including spaces.

Question 4

Question 1(iv)The keyword used to call package in the program:extendsexportimportpackage

Accepted Answer

importReason — import keyword is used to import built-in and user-defined packages into our Java program.

Question 5

Question 1(v)What value will Math.sqrt(Math.ceil(15.3)) return?16.0164.05.0

Accepted Answer

4.0Reason — Math.ceil method returns the smallest double value that is greater than or equal to the argument and Math.sqrt method returns the square root of its argument as a double value. Thus the given expression is evaluated as follows:Math.sqrt(Math.ceil (15.3))= Math.sqrt(16.0)= 4.0

Question 6

Question 1(vi)The absence of which statement leads to fall through situation in switch case statement?continuebreakreturnSystem.exit(0)

Accepted Answer

breakReason — The absence of break statement leads to fall through situation in switch case statement.

Question 7

Question 1(vii)State the type of loop in the given program segment:for (int i = 5; i != 0; i -= 2)
    System.out.println(i);
finiteinfinitenullfixed

Accepted Answer

infiniteReason — The given loop is an example of infinite loop as for each consecutive iteration of for loop, the value of i will be updates as follows:IterationValue of iRemark15Initial value of i = 523i = 5 - 2 = 331i = 3 - 2 = 14-1i = 1 - 2 = -15-3i = -1 - 2 = -3 and so on...Since i will never be '0', the loop will execute infinitely.

Question 8

Question 1(viii)Write a method prototype name check() which takes an integer argument and returns a char:char check()void check (int x)check (int x)char check (int x)

Accepted Answer

char check (int x)Reason — The prototype of a function is written in the given syntax:return_type method_name(arguments)Thus, the method has the prototype given below:char check (int x)

Question 9

Question 1(ix)The number of values that a method can return is:1234

Accepted Answer

1Reason — A method can return only one value.

Question 10

Question 1(x)Predict the output of the following code snippet:String P = "20", Q ="22"; 
int a = Integer.parseInt(P);
int b = Integer.valueOf(Q);
System.out.println(a + " " + b);2020 22222022

Accepted Answer

20 22Reason — The values of strings P and Q are converted into integers using the Integer.parseInt() method and stored in int variables a and b, respectively.When the statement System.out.println(a + " " + b) is executed, first the operation a + " " is performed. Here, int variable a is converted to a string and a space is concatenated to it resulting in "20 ".After this, the operation "20 " + b is performed resulting in 20 22 which is printed as the output.

Question 11

Question 1(xi)The String class method to join two strings is:concat(String)<string>.joint(string)concat(char)Concat()

Accepted Answer

concat(String)Reason — concat() method is used to join two strings. Its syntax is as follows:String1.concat(String2)

Question 12

Question 1(xii)The output of the function "COMPOSITION".substring(3, 6):POSIPOSMPOMPOS

Accepted Answer

POSReason — The substring() method returns a substring beginning from the startindex and extending to the character at endIndex - 1. Since a string index begins at 0, the character at index 3 is 'P' and the character at index 5 (6-1 = 5) is 'S'. Thus, "POS" is extracted.

Question 13

Question 1(xiii)int x = (int)32.8; is an example of ............... typecasting.implicitautomaticexplicitcoercion

Accepted Answer

explicitReason — In explicit type conversion, the data gets converted to a type as specified by the programmer. Here, the float value 32.8 is being converted to int type by the programmer, explicitly.

Question 14

Question 1(xiv)The code obtained after compilation is known as:source codeobject codemachine codejava byte code

Accepted Answer

java byte codeReason — Java compiler converts Java source code into an intermediate binary code called Bytecode after compilation.

Question 15

Question 1(xv)Missing a semicolon in a statement is what type of error?LogicalSyntaxRuntimeNo error

Accepted Answer

SyntaxReason — Syntax Errors occur when we violate the rules of writing the statements of the programming language. Missing a semicolon in a statement is a syntax error.

Question 16

Question 1(xvi)Consider the following program segment and select the output of the same when n = 10 :switch(n)
{
    case 10 : System.out.println(n*2); 
    case 4 : System.out.println(n*4); break; 
    default : System.out.println(n);
}204010420, 401010

Accepted Answer

20
40
Reason — Since n = 10, case 10 will be executed. It prints 20 (10 * 2) on the screen. Since break statement is missing, the execution falls through to the next case. Case 4 prints 40 (10 * 4) on the screen. Now the control finds the break statement and the control comes out of the switch statement.

Question 17

Question 1(xvii)A method which does not modify the value of variables is termed as:Impure methodPure methodPrimitive methodUser defined method

Accepted Answer

Pure methodReason — A method which does not modify the value of variables is termed as a pure method.

Question 18

Question 1(xviii)When an object of a Wrapper class is converted to its corresponding primitive data type, it is called as ............... .BoxingExplicit type conversionUnboxingImplicit type conversion

Accepted Answer

UnboxingReason — When an object of a Wrapper class is converted to its corresponding primitive data type, it is called as unboxing.

Question 19

Question 1(xix)The number of bits occupied by the value ‘a’ are:1 bit2 bits4 bits16 bits

Accepted Answer

16 bitsReason — A char data type occupies 2 bytes in the memory.1 byte = 8 bits2 bytes = 8 * 2 = 16 bits

Question 20

Question 1(xx)Method which is a part of a class rather than an instance of the class is termed as:Static methodNon static methodWrapper classString method

Accepted Answer

Static methodReason — Method which is a part of a class rather than an instance of the class is termed as Static method.

Solved 2023 Question Paper ICSE Class 10 Computer Applications