ICSE Class 10 Mathematics
Question 19 of 49
Multiple-Choice Questions — Question 19
Back to all questionsGiven,
Sum of n terms of an arithmetic progression Sn = n2 - n.
S1 = 12 - 1 = 0,
S2 = 22 - 2 = 4 - 2 = 2,
S3 = 32 - 3 = 9 - 3 = 6.
Sum upto first term = First term = 0.
Given, sum upto 2 terms = 2 and first term = 0, second term = 2.
Sum upto third term = 6
∴ First term + Second term + Third term = 6
⇒ 0 + 2 + Third term = 6
⇒ Third term = 6 - 2 = 4.
Hence, Option 2 is the correct option.