Question 104The daily wages of workers in a construction unit were recorded as follows :Class marks (Wages)No. of workers4256475125251557517625767513Form a frequency distribution table with class intervals and find modal wage by plotting a histogram.

Question

Accepted Answer

Difference between two consecutive class marks = 475 - 425 = 50.

Adjustment factor = $\dfrac{\text{Class width}}{2} = \dfrac{50}{2}$ = 25.

Lower class limit = Class mark - Adjustment factor

Upper class limit = Class mark + Adjustment factor

Class	Frequency
400-450	6
450-500	12
500-550	15
550-600	17
600-650	7
650-700	3

Steps of construction :

Take 2 cm along x-axis = ₹50 and 2 cm along y-axis = 5 workers.
Construct rectangles corresponding to the given data.
In highest rectangle, draw two st. lines AD and BC from corners of the rectangles on either side of the highest rectangle to the opposite corners of the highest rectangle.
Let K be the point of intersection of AD and BC. Through K, draw a vertical line to meet the x-axis at L. The abscissa of the point L represents 557.50.

The daily wages of workers in a construction unit were recorded as follows : Maths Competency Focused Practice Questions Class 10 Solutions.

Hence, mode = ₹ 557.50

Class marks (Wages)	No. of workers
425	6
475	12
525	15
575	17
625	7
675	13

Short Answer Questions 2 — Question 27

Question 104