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ICSE Class 10 Mathematics Question 6 of 28

Short Answer Questions 2 — Question 6

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Question 83

The profit in rupees in a local restaurant and the number of customers who visited the restaurant are tabulated below for each week for one month.

Week numberWeek 1Week 2Week 3Week 4
Number of customers14005600x3212
Profit in ₹2800011200032140y

Find :

(a) if the number of customers and profit per week in continued proportion or not? Justify your answer.

(b) the value of x and y.

Answer

(a) Since,

140028000=5600112000=120\dfrac{1400}{28000} = \dfrac{5600}{112000} = \dfrac{1}{20}.

Hence, number of customers and profit per week are in proportion but not in continued proportion.

(b) As,

Number of customers and profit per week are in proportion.

∴x32140=120⇒x=32140×120=1607\therefore \dfrac{x}{32140} = \dfrac{1}{20} \\[1em] \Rightarrow x = 32140 \times \dfrac{1}{20} = 1607 \\[1em]

and

∴3212y=120⇒y=3212×20=64240.\therefore \dfrac{3212}{y} = \dfrac{1}{20} \\[1em] \Rightarrow y = 3212 \times 20 = 64240.

Hence, x = 1607 and y = 64240.