ICSE Class 10 Mathematics Question 11 of 21

Solved 2025 Specimen Paper ICSE Class 10 Mathematics — Question 2

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Question

Question 4(ii)

Solve the following inequation, write the solution set and represent it on the real number line.

5x - 21 < 5x7−6≤−337+x\dfrac{5x}{7} - 6 \le -3\dfrac{3}{7} + x, x ∈ R.

Answer

Given, inequation : 5x - 21 < 5x7−6≤−337+x\dfrac{5x}{7} - 6 \le -3\dfrac{3}{7} + x

Solving L.H.S. of the inequation :

⇒5x−21<5x7−6⇒5x−5x7<21−6⇒35x−5x7<15⇒30x7<15⇒x<7×1530⇒x<72 ..........(1)\Rightarrow 5x - 21 \lt \dfrac{5x}{7} - 6\\[1em] \Rightarrow 5x - \dfrac{5x}{7} \lt 21 - 6 \\[1em] \Rightarrow \dfrac{35x - 5x}{7} \lt 15 \\[1em] \Rightarrow \dfrac{30x}{7} \lt 15 \\[1em] \Rightarrow x \lt \dfrac{7 \times 15}{30} \\[1em] \Rightarrow x \lt \dfrac{7}{2} \text{ ..........(1)}

Solving R.H.S. of the inequation :

⇒5x7−6≤−337+x⇒5x7−6≤−247+x⇒x−5x7≥−6+247⇒7x−5x7≥−42+247⇒2x7≥−187⇒2x≥−18⇒x≥−182⇒x≥−9 ..........(2)\Rightarrow \dfrac{5x}{7} - 6 \le -3\dfrac{3}{7} + x \\[1em] \Rightarrow \dfrac{5x}{7} - 6 \le -\dfrac{24}{7} + x \\[1em] \Rightarrow x - \dfrac{5x}{7} \ge -6 + \dfrac{24}{7} \\[1em] \Rightarrow \dfrac{7x - 5x}{7} \ge \dfrac{-42 + 24}{7} \\[1em] \Rightarrow \dfrac{2x}{7} \ge \dfrac{-18}{7} \\[1em] \Rightarrow 2x \ge -18 \\[1em] \Rightarrow x \ge \dfrac{-18}{2} \\[1em] \Rightarrow x \ge -9 \text{ ..........(2)}

From equation (1) and (2),

Solution set = {x : -9 ≤ x < 72\dfrac{7}{2}, x ∈ R}

Solve the following inequation, write the solution set and represent it on the real number line. ICSE 2025 Maths Solved Question Paper.

Hence, solution set = {x : -9 ≤ x < 72\dfrac{7}{2}, x ∈ R}.

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