The primary coil of a transformer has 800 turns and the secondary coil has 8 turns. It is connected to a 220 V a.c. supply. What will be the output voltage?
Given,
Np = 800
Ns = 8
Ep = 220 V
Es = ?
Now,
EsEp=NsNp\dfrac{E_s}{E_p} = \dfrac{N_s}{N_p}EpEs=NpNs
Substituting the values in the formula we get,
Es220=8800⇒Es=220×8800⇒Es=2.2V\dfrac{E_s}{220} = \dfrac{8}{800} \\[0.5em] \Rightarrow E_s = 220 \times \dfrac{8}{800} \\[0.5em] \Rightarrow E_s = 2.2 V \\[0.5em]220Es=8008⇒Es=220×8008⇒Es=2.2V
Hence, output voltage = 2.2 V
