ICSE Class 10 Physics Question 15 of 20

Force — Question 17

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Question

Question 17

A uniform metre rule of weight 10 gf is pivoted at its 0 mark.

(i) What moment of force depresses the rule?

(ii) How can it be made horizontal by applying a least force?

Answer

(i) Moment of force = Fr

Substituting the values of F and r we get,

10gf×50cm=500gfcm10gf \times 50cm = 500gfcm

(ii) In order to make the rule horizontal by applying least force distance has to be max as moment of force will remain same.

So,

F=500100=5gfF = \dfrac{500}{100} = 5gf

Therefore, a force of 5 gf upwards at 100 cm can balance the rule.