Refraction of Light at Plane Surfaces — Question 3

As we know,

$\text {Shift} = \text {Real depth} \times (1 – \dfrac{1}{_aμ_m})$

Given,

Shift in the image = 7 mm or 0.7 cm

Refractive index of the glass block = 1.5

So, substituting the values in the formula we get,

$0.7 = \text {Real depth} \times (1 – \dfrac{1}{1.5}) \\[0.5em] 0.7 = \text {Real depth} \times \dfrac{0.5}{1.5} \\[0.5em] \text {Real depth} = \dfrac{0.7 \times 1.5}{0.5} \\[0.5em] \Rightarrow \text {Real depth} = 2.1 \\[0.5em]$

Hence, the thickness of glass slab = 2.1 cm.
(Thickness of glass slab is same as the real depth of the postage stamp).