Refraction of Light at Plane Surfaces — Question 4

As we know that,

$<em>{\text{a}}\text{μ}</em>{\text{g}} = \dfrac{\text {wavelength of light in air}}{\text {wavelength of light in glass}} \\[0.5em]$

Given,

Refractive index of glass with respect to air is given by _aμ_g = $\dfrac{3}{2}$

Wavelength of light in air = 6600 Å

Substituting the values in the formula above we get,

$\dfrac{3}{2} = \dfrac{\text {wavelength of light in air}}{\text{wavelength of light in glass}} \\[0.5em] \dfrac{3}{2} = \dfrac{6600}{\text {wavelength of light in glass}} \\[0.5em] \text {wavelength of light in glass} = \dfrac{6600}{\dfrac{3}{2}} \\[0.5em] \text {wavelength of light in glass} = 6600 \times \dfrac{2}{3} \\[0.5em] \text {wavelength of light in glass} = 4400 \\[0.5em]$

Hence, wavelength of light in glass = 4400 Å