ICSE Class 10 Physics
Question 2 of 20
Solved 2016 Question Paper ICSE Class 10 Physics — Question 4
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Question Question 1(d)
Calculate the mass of ice required to lower the temperature of 300 g of water at 40°C to water at 0°C. (Specific latent heat of ice = 336 J g-1, Specific heat capacity of water = 4.2 J g-1 °C-1) [2]
Given,
mass of water m = 300 g
initial temperature = 40°C
final temperature = 0°C
Therefore, fall in temperature = 40 - 0 = 40 °C
Heat lost by water = m x c x Δt
= 300 x 4.2 x 40 = 5.04 x 104 J
If m' g ice is added, heat gained by it to melt to 0 °C = m'L = m' x 336 J
By the principle of method of mixture,
heat lost by water = heat gained by ice
Therefore, 5.04 x 104 = m' x 336
m' = = 150 g