ICSE Class 10 Physics
Question 4 of 15
Solved 2022 Semester 2 Question Paper ICSE Class 10 Physics — Question 3
Back to all questions(a) 12Ω and 8Ω are in parallel.
= + = =
So the equivalent resistance = = 4.8Ω
2Ω is in series with this combination.
Hence the total resistance = 2 + 4.8 = 6.8Ω
(b) Potential difference across the 12Ω resistor = potential difference across 8Ω resistor
Or, 12 × 0.4 = 8 × I2
∴ I2 = = = 0.6 A
(c) Current I = I1 + I2 = 0.4 + 0.6 = 1 A
