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ICSE Class 10 Physics Question 1 of 27

Solved 2024 Question Paper ICSE Class 10 Physics — Question 2

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2
Question

Question 1(ii)

A door lock is opened by turning the lever (handle) of length 0.2 m. If the moment of force produced is 1 Nm, then the minimum force required is:

  1. 5 N
  2. 10 N
  3. 20 N
  4. 0.2 N
Answer

5 N

Reason —

Given,

Length of lever = Perpendicular distance of the line of action of the force = 0.2 m
Moment of force = 1 Nm
As, Moment of force = Force × Perpendicular distance of the line of action of the force

1 = force x 0.2

force = 10.2=102\dfrac{1}{0.2}=\dfrac{10}{2} = 5 N