How much heat is required to convert 500 g of ice at 0°C to water at 0°C? The latent heat of fusion of ice is 330 J g⁻¹.
Given,
m = 500 g
latent heat of fusion of ice (L) = 330 J g⁻¹
Let, required heat be Q.
Then,
Q=mL=500×330=165000 J=165 kJ\text Q = \text {mL} = 500 \times 330 = 165000\ \text J = 165\ \text {kJ}Q=mL=500×330=165000 J=165 kJ
