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Question Question 3(v)
Study the following electric circuit. Find the reading of
(a) the ammeter and
(b) the voltmeter

(a) In the given circuit, resistances are connected in series, hence, equivalent resistances (Re) = R1 + R2 = 4 + 2 = 6 Ω
Potential difference (V) = 3 V
Current (I) = ?
From Ohm's law
V = IR
Substituting the values in the formula above, we get,
As in series combination, current flowing through each component is same and is equal to the total current flowing in the circuit hence, the reading of ammeter = 0.5 A
(b) Reading of voltmeter = Potential difference across 2 Ω resistor.
Current flowing through bulb = 0.5 A
From Ohm's law
V = IR
Substituting the values in the formula above, we get,
V = 0.5 x 2 = 1 V
Hence, the reading of voltmeter = 1 V