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ICSE Class 10 Physics Question 2 of 27

Solved Sample Paper 2 — Question 6

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6
Question

Question 1(vi)

A ray of light incident at an angle of 48° on a prism of refracting angle 60°, suffers minimum deviation. The angle of minimum deviation would be

  1. 12°
  2. 24°
  3. 36°
  4. 48°
Answer

36°

Reason — As we know,
δmin=2i−Aδ_ {min} = 2i - A

Given,

i = 48°

A = 60°

So, substituting the values in the formula above we get,

δmin=(2×48°)−60°δmin=96°−60°⇒δmin=36°δ_ {min} = (2 \times 48°) - 60° \\[0.5em] δ_ {min} = 96° - 60° \\[0.5em] \Rightarrow δ_ {min} = 36° \\[0.5em]

Hence, the angle of minimum deviation is equal to 36°