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ICSE Class 10 Physics Question 7 of 27

Solved Sample Paper 2 — Question 18

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18
Question

Question 2(iii)

The moment of a force of 20 N about a point O is 18 N-m. Find the distance of point of application of the force from the point O.

Answer

Given,

moment of a force = 18 N-m

force = 20 N

distance = ?

Moment of force = force × distance

Substituting the values in the formula above, we get,

18=20×d⇒d=1820⇒d=0.9 m18 = 20 \times \text{d} \\[0.5em] \Rightarrow d = \dfrac{18}{20} \\[0.5em] \Rightarrow d = 0.9 \text{ m} \\[0.5em]

Hence, distance of point of application of the force from the point O = 0.9 m