Q: Question 1A Goldbach number is a positive even integer that can be expressed as the sum of two odd primes.Note: All even integer numbers greater than 4 are Goldbach numbers.Example:6 = 3 + 310 = 3 + 710 = 5 + 5Hence, 6 has one odd prime pair 3 and 3. Similarly, 10 has two odd prime pairs, i.e. 3 and 7, 5 and 5.Write a program to accept an even integer 'N' where N > 9 and N < 50. Find all the odd prime pairs whose sum is equal to the number 'N'.Test your program with the following data and some random data:Example 1INPUT:N = 14OUTPUT:PRIME PAIRS ARE:3, 117, 7Example 2INPUT:N = 30OUTPUT:PRIME PAIRS ARE:7, 2311, 1913, 17Example 3INPUT:N = 17OUTPUT:INVALID INPUT. NUMBER IS ODD.Example 4INPUT:N = 126OUTPUT:INVALID INPUT. NUMBER OUT OF RANGE.Solutionimport java.util.Scanner; public class GoldbachNumber { public static boolean isPrime(int num) { int c = 0; for (int i = 1; i <= num; i++) { if (num % i == 0) { c++; } } return c == 2; } public static void main(String args[]) { Scanner in = new Scanner(System.in); System.out.print("ENTER THE VALUE OF N: "); int n = in.nextInt(); if (n <= 9 || n >= 50) { System.out.println("INVALID INPUT. NUMBER OUT OF RANGE."); return; } if (n % 2 != 0) { System.out.println("INVALID INPUT. NUMBER IS ODD."); return; } System.out.println("PRIME PAIRS ARE:"); int a = 3; int b = 0; while (a <= n / 2) { b = n - a; if (isPrime(a) && isPrime(b)) { System.out.println(a + ", " + b); } a += 2; } } }Output

importjava.util.Scanner;publicclassGoldbachNumber{publicstaticbooleanisPrime(intnum) {intc=0;for(inti=1; inum; i++) {if(num%i==0) { c++; } }returnc==2; }publicstaticvoidmain(Stringargs[]) {Scannerin=newScanner(System.in);System.out.print("ENTER THE VALUE OF N:");intn=in.nextInt();if(n9||n>=50) {System.out.println("INVALID INPUT. NUMBER OUT OF RANGE.");return; }if(n%2!=0) {System.out.println("INVALID INPUT. NUMBER IS ODD.");return; }System.out.println("PRIME PAIRS ARE:");inta=3;intb=0;while(an/2) { b=n-a;if(isPrime(a)&&isPrime(b)) {System.out.println(a+","+b); } a+=2; } }}Output

Question 1

Question 1A Goldbach number is a positive even integer that can be expressed as the sum of two odd primes.Note: All even integer numbers greater than 4 are Goldbach numbers.Example:6 = 3 + 310 = 3 + 710 = 5 + 5Hence, 6 has one odd prime pair 3 and 3. Similarly, 10 has two odd prime pairs, i.e. 3 and 7, 5 and 5.Write a program to accept an even integer 'N' where N > 9 and N < 50. Find all the odd prime pairs whose sum is equal to the number 'N'.Test your program with the following data and some random data:Example 1INPUT:N = 14OUTPUT:PRIME PAIRS ARE:3, 117, 7Example 2INPUT:N = 30OUTPUT:PRIME PAIRS ARE:7, 2311, 1913, 17Example 3INPUT:N = 17OUTPUT:INVALID INPUT. NUMBER IS ODD.Example 4INPUT:N = 126OUTPUT:INVALID INPUT. NUMBER OUT OF RANGE.Solutionimport java.util.Scanner; public class GoldbachNumber { public static boolean isPrime(int num) { int c = 0; for (int i = 1; i <= num; i++) { if (num % i == 0) { c++; } } return c == 2; } public static void main(String args[]) { Scanner in = new Scanner(System.in); System.out.print("ENTER THE VALUE OF N: "); int n = in.nextInt(); if (n <= 9 || n >= 50) { System.out.println("INVALID INPUT. NUMBER OUT OF RANGE."); return; } if (n % 2 != 0) { System.out.println("INVALID INPUT. NUMBER IS ODD."); return; } System.out.println("PRIME PAIRS ARE:"); int a = 3; int b = 0; while (a <= n / 2) { b = n - a; if (isPrime(a) && isPrime(b)) { System.out.println(a + ", " + b); } a += 2; } } }Output

Accepted Answer

importjava.util.Scanner;publicclassGoldbachNumber{publicstaticbooleanisPrime(intnum) {intc=0;for(inti=1; inum; i++) {if(num%i==0) {                c++;            }        }returnc==2;    }publicstaticvoidmain(Stringargs[]) {Scannerin=newScanner(System.in);System.out.print("ENTER THE VALUE OF N:");intn=in.nextInt();if(n9||n>=50) {System.out.println("INVALID INPUT. NUMBER OUT OF RANGE.");return;        }if(n%2!=0) {System.out.println("INVALID INPUT. NUMBER IS ODD.");return;        }System.out.println("PRIME PAIRS ARE:");inta=3;intb=0;while(an/2) {            b=n-a;if(isPrime(a)&&isPrime(b)) {System.out.println(a+","+b);            }                        a+=2;        }    }}Output

Question 2

Question 2Write a program to declare a matrix a[][] of order (m × n) where 'm' is the number of rows and 'n' is the number of columns such that the values of both 'm' and 'n' must be greater than 2 and less than 10. Allow the user to input integers into this matrix. Perform the following tasks on the matrix:Display the original matrix.Sort each row of the matrix in ascending order using any standard sorting technique.Display the changed matrix after sorting each row.Test your program for the following data and some random data:Example 1INPUT:M = 4N = 3ENTER ELEMENTS OF MATRIX:11−235167904318\begin{matrix} 11 & -2 & 3 \ 5 & 16 & 7 \ 9 & 0 & 4 \ 3 & 1 & 8 \end{matrix}11593−216013748OUTPUT:ORIGINAL MATRIX11−235167904318\begin{matrix} 11 & -2 & 3 \ 5 & 16 & 7 \ 9 & 0 & 4 \ 3 & 1 & 8 \end{matrix}11593−216013748MATRIX AFTER SORTING ROWS−23115716049138\begin{matrix} -2 & 3 & 11 \ 5 & 7 & 16 \ 0 & 4 & 9 \ 1 & 3 & 8 \end{matrix}−25013743111698Example 2INPUT:M = 3N = 3ENTER ELEMENTS OF MATRIX22519736129136\begin{matrix} 22 & 5 & 19 \ 7 & 36 & 12 \ 9 & 13 & 6 \end{matrix}22795361319126OUTPUT:ORIGINAL MATRIX22519736129136\begin{matrix} 22 & 5 & 19 \ 7 & 36 & 12 \ 9 & 13 & 6 \end{matrix}22795361319126MATRIX AFTER SORTING ROWS51922712366913\begin{matrix} 5 & 19 & 22 \ 7 & 12 & 36 \ 6 & 9 & 13 \end{matrix}57619129223613Example 3INPUT:M = 11N = 5OUTPUT:MATRIX SIZE OUT OF RANGE.Solutionimport java.util.Scanner; public class ArraySort { public static void main(String args[]) { Scanner in = new Scanner(System.in); System.out.print("ENTER THE VALUE OF M: "); int m = in.nextInt(); System.out.print("ENTER THE VALUE OF N: "); int n = in.nextInt(); if (m <= 2 || m >= 10 || n <= 2 || n >= 10) { System.out.println("MATRIX SIZE OUT OF RANGE."); return; } int a[][] = new int[m][n]; System.out.println("ENTER ELEMENTS OF MATRIX:"); for (int i = 0; i < m; i++) { System.out.println("ENTER ELEMENTS OF ROW " + (i+1) + ":"); for (int j = 0; j < n; j++) { a[i][j] = in.nextInt(); } } System.out.println("ORIGINAL MATRIX"); for (int i = 0; i < m; i++) { for (int j = 0; j < n; j++) { System.out.print(a[i][j] + " "); } System.out.println(); } for (int i = 0; i < m; i++) { for (int j = 0; j < n - 1; j++) { for (int k = 0; k < n - j - 1; k++) { if (a[i][k] > a[i][k + 1]) { int t = a[i][k]; a[i][k] = a[i][k+1]; a[i][k+1] = t; } } } } System.out.println("MATRIX AFTER SORTING ROWS"); for (int i = 0; i < m; i++) { for (int j = 0; j < n; j++) { System.out.print(a[i][j] + " "); } System.out.println(); } } }Output

Accepted Answer

importjava.util.Scanner;publicclassArraySort{publicstaticvoidmain(Stringargs[]) {Scannerin=newScanner(System.in);System.out.print("ENTER THE VALUE OF M:");intm=in.nextInt();System.out.print("ENTER THE VALUE OF N:");intn=in.nextInt();if(m2||m>=10||n2||n>=10) {System.out.println("MATRIX SIZE OUT OF RANGE.");return;        }inta[][]=newint[m][n];System.out.println("ENTER ELEMENTS OF MATRIX:");for(inti=0; im; i++) {System.out.println("ENTER ELEMENTS OF ROW"+(i+1)+":");for(intj=0; jn; j++) {                a[i][j]=in.nextInt();            }        }System.out.println("ORIGINAL MATRIX");for(inti=0; im; i++) {for(intj=0; jn; j++) {System.out.print(a[i][j]+"");            }System.out.println();        }for(inti=0; im; i++) {for(intj=0; jn-1; j++) {for(intk=0; kn-j-1; k++) {if(a[i][k]>a[i][k+1]) {intt=a[i][k];                        a[i][k]=a[i][k+1];                        a[i][k+1]=t;                    }                }             }        }System.out.println("MATRIX AFTER SORTING ROWS");for(inti=0; im; i++) {for(intj=0; jn; j++) {System.out.print(a[i][j]+"");            }System.out.println();        }    }}Output

Question 3

Question 3The names of the teams participating in a competition should be displayed on a banner vertically, to accommodate as many teams as possible in a single banner. Design a program to accept the names of N teams, where 2 < N < 9 and display them in vertical order, side by side with a horizontal tab (i.e. eight spaces).Test your program for the following data and some random data:Example 1INPUT:N = 3Team 1: EmusTeam 2: Road RolsTeam 3: CoyoteOUTPUT:E R Cm o ou a ys d o t R e o l s Example 2INPUT:N = 4Team 1: RoyalTeam 2: MarsTeam 3: De RoseTeam 4: KingsOUTPUT:R M D Ko a e iy r na s R gl o s s e Example 3INPUT:N = 10OUTPUT:INVALID INPUTSolutionimport java.util.Scanner; public class Banner { public static void main(String args[]) { Scanner in = new Scanner(System.in); System.out.print("ENTER THE VALUE OF N: "); int n = in.nextInt(); in.nextLine(); if (n <= 2 || n >= 9) { System.out.println("INVALID INPUT"); return; } String teams[] = new String[n]; int highLen = 0; for (int i = 0; i < n; i++) { System.out.print("Team " + (i+1) + ": "); teams[i] = in.nextLine(); if (teams[i].length() > highLen) { highLen = teams[i].length(); } } for (int i = 0; i < highLen; i++) { for (int j = 0; j < n; j++) { int len = teams[j].length(); if (i >= len) { System.out.print(" "); } else { System.out.print(teams[j].charAt(i) + " "); } } System.out.println(); } } }Output

Accepted Answer

importjava.util.Scanner;publicclassBanner{publicstaticvoidmain(Stringargs[]) {Scannerin=newScanner(System.in);System.out.print("ENTER THE VALUE OF N:");intn=in.nextInt();        in.nextLine();if(n2||n>=9) {System.out.println("INVALID INPUT");return;        }Stringteams[]=newString[n];inthighLen=0;for(inti=0; in; i++) {System.out.print("Team"+(i+1)+":");             teams[i]=in.nextLine();if(teams[i].length()>highLen) {                 highLen=teams[i].length();             }        }for(inti=0; ihighLen; i++) {for(intj=0; jn; j++) {intlen=teams[j].length();if(i>=len) {System.out.print("	");                }else{System.out.print(teams[j].charAt(i)+"	");                }            }System.out.println();        }    }}Output

Solved 2018 Practical Paper ISC Computer Science