Motion — Question 3

Average speed = 10 m s^-1;
time = 20 min
1 min = 60 sec
20 min = 60 x 20 = 1200 sec
distance = ?

$\text{Average speed} = \dfrac{\text{distance}}{\text{time}} \\[1em] \text{10} = \dfrac{\text{distance}}{\text{1200}} \\[1em] \text{distance} = 1200 \times 10 = 12000 \text{m}$

So, distance covered = 12000 m or 12 km.