Calculate the pressure in pascal exerted by a force of 300 N acting normally on an area of 30 cm2.
Given:Thrust = 300 NArea = 30 cm2 = 3010000\dfrac{30}{10000}1000030 = 0.003 m2Pressure = ?
Pressure=ThrustArea=3000.003=1,00,000 Pa\text{Pressure}= \dfrac{\text{Thrust}}{\text{Area}} \\[1em] = \dfrac{300}{0.003} \\[1em] = 1,00,000 \text{ Pa}Pressure=AreaThrust=0.003300=1,00,000 Pa
So Pressure = 1,00,000 Pa or 105 Pa.