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ICSE Class 9 Chemistry Question 16 of 22

Atomic Structure — Question 14

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14
Question

Question 1(1991)

Write down the electronic configuration of the following:

(i) 1327X^{27}_{13}\text{X},

(ii) 1735Y^{35}_{17}\text{Y}.

Write down the number of electrons in X and neutrons in Y and the formula of the compound formed by X and Y.

Answer

(i) 1327X^{27}_{13}\text{X} = [2, 8, 3] ; Number of electrons in X = 13

(ii) 1735Y^{35}_{17}\text{Y} = [2, 8, 7] ; Number of neutrons = A - Z = 35 - 17 = 18

Valency of 1327X^{27}_{13}\text{X} = [2, 8, 3] = 3 positive

Valency of 1735Y^{35}_{17}\text{Y} = [2, 8, 7] = 1 negative.

Formula of the compound:

X3+↗Y1−X33 ↘↙ Y1⇒X11 ↘↙ Y3\text{X}^{3+} \phantom{\nearrow} \text{Y}^{1-} \\[0.5em] \overset{\phantom{3}{3}}{\text{X}} \space {\searrow}\mathllap{\swarrow} \space \overset{1}{\text{Y}} \Rightarrow \underset{\phantom{1}{1}}{\text{X}} \space {\searrow}\mathllap{\swarrow} \space \underset{3}{\text{Y}} \\[0.5em]

So, we get the formula as XY3\bold{XY}_\bold{3}