Atomic Structure and Chemical Bonding — Question 6
Back to all questionsIn the formation of (i) Oxygen molecule (ii) Carbon tetrachloride molecule, state the following:
(a) Electronic configuration of nearest inert gas attained.
(b) How many electrons are shared/transferred in bond formation?
(c) Which type of bonds these compounds form?
(d) Draw the orbital diagrams?
(i) In the formation of Oxygen molecule:
(a) Neon (10) 2,8, because electronic configuration of oxygen is [2,6] so to attain the stable configuration of nearest noble gas Neon, oxygen needs two electrons.
(b) Two pairs of electrons are shared, and both oxygen atoms attain their octet.
(c) Double Covalent bond, as the bond between two oxygen atoms is formed by sharing of electrons.
(d) Orbital Diagram of the formation of Oxygen molecule:
(ii) In the formation of Carbon tetra chloride molecule:
| Atoms involved | Electronic configuration | Nearest noble gas |
|---|---|---|
| Carbon | C [2,4] | Neon [2,8] |
| Chlorine | Cl [2,8,7] | Argon [2,8,8] |
(b) Four pair of electrons are shared, as carbon needs four electrons and chlorine needs one electron to complete their octet, hence four chlorine atoms share their one electron each with carbon and all the atoms attain a stable configuration.
(c) Single Covalent bond, as the bond between carbon and 4 chlorine atoms is formed by sharing one pair of electrons.
(d) Orbital Diagram of the formation of Carbon tetrachloride molecule:
