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ICSE Class 9 Chemistry Question 40 of 55

ICSE Questions Set in Previous Years — Question 40

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Question

Question 40

The pressure of one mole of gas at STP is doubled and the temperature is raised to 546 K. What is the final volume of the gas ? [one mole of a gas occupies a volume of 22.4 litres at STP].

Answer

Initial conditions [S.T.P.] :

P1 = Initial pressure of the gas = 1 atm
V1 = Initial volume of the gas = 22.4 litres
T1 = Initial temperature of the gas = 273 K

Final conditions:

P2 (Final pressure) = 2 atm
V2 (Final volume) = ?
T2 (Final temperature) = 546 K

By Gas Law:

P1×V1T1=P2×V2T2\dfrac{\text{P}_1\times\text{V}_1}{\text{T}_1} = \dfrac{\text{P}_2\times\text{V}_2}{\text{T}_2}

Substituting the values :

1×22.4273=2×V2546V2=1×22.4×546273×2V2=22.4 lit\dfrac{1 \times 22.4}{273} = \dfrac{2\times \text{V}_2}{546}\\[0.5em] \text{V}_2 = \dfrac{1 \times 22.4\times 546}{273\times 2} \\[0.5em] \text{V}_2 = 22.4 \text{ lit}

∴ Final volume of the gas = 22.4 lit.