Study of Gas Laws — Question 16

V₁ = 2500 cm³

P₁ = 760 mm Hg

P₂ = increased by two and a half times

= (1 + $2\dfrac{1}{2}$ ) times of 760 mm Hg

= (1 + $\dfrac{5}{2}$ ) times of 760 mm Hg

= ( $\dfrac{7}{2}$ x 760) mm Hg

V₂ = ?

By Boyle's Law:

$\text{P}_1 \text{V}_1 = \text{P}_2 \text{V}_2$

Substituting the values :

$760 \times 2500 = \dfrac{7}{2} \times 760 \times \text{V}_2 \\[1em] \text{V}_2 = \dfrac{5000}{7} \\[0.5em]$

∴ Final volume = $\dfrac{5000}{7}$ cm³