The Language of Chemistry — Question 25

(a) Chemical formula of Oxide of A:

$\text{A}^{4+} \space \text{O}^{2-} \\[1em] \text{Dividing by H.C.F. it becomes} \\[1em] \text{A}^{2+} \space \text{O}^{1-}\\[1em] \overset{{2}}{\text{A}} \space {\swarrow}\mathllap{\searrow} \space \overset{1}{\text{O}} \Rightarrow \underset{\phantom{2}{1}}{\text{A}} \space {\swarrow}\mathllap{\searrow} \underset{\phantom{2}{2}}{\text{O}} \\[1em] \text{AO}_2$

∴ Chemical formula of Oxide of A is AO₂

(b) Chemical formula of Nitrate of A:

$\text{A}^{4+} \space \text{NO}_3^{1-} \\[1em] \overset{{4}}{\text{A}} \space {\swarrow}\mathllap{\searrow} \space \overset{1}{\text{NO}_3} \Rightarrow \underset{\phantom{2}{1}}{\text{A}} \space {\swarrow}\mathllap{\searrow} \underset{\phantom{2}{4}}{\text{NO}_3} \\[1em] \text{A(NO}_3)_4$

∴ Chemical formula of Nitrate of A is A(NO₃)₄

(c) Chemical formula of Phosphate of A:

$\text{A}^{4+} \space \text{PO}_4^{3-} \\[1em] \overset{{4}}{\text{A}} \space {\swarrow}\mathllap{\searrow} \space \overset{3}{\text{PO}_4} \Rightarrow \underset{\phantom{2}{3}}{\text{A}} \space {\swarrow}\mathllap{\searrow} \underset{\phantom{2}{4}}{\text{PO}_4} \\[1em] \text{A}_3(\text{PO}_4)_4$

∴ Chemical formula of Phosphate of A is A₃(PO₄)₄