Bright Tutorials Bright Tutorials
ICSE Class 9 Chemistry Question 30 of 34

The Language of Chemistry — Question 6

Back to all questions
6
Question

Question 6

Urea is a very important nitrogenous fertilizer. Its formula is CON2H4. Calculate the percentage of carbon in urea.

(C= 12, O = 16, N = 14 and H = 1)

Answer

Relative molecular mass of CON2H4
   = 12 + 16 + 2 x 14 + 4 x 1
   = 12 + 16 + 28 + 4
   = 60 amu

Wt. of C in CON2H4 = 12 g

% of C = Wt. of CTotal Wt. of CON2H4×100\dfrac{\text{Wt. of C}}{\text{Total Wt. of CON}_2\text{H}_4}\times 100

= 1260\dfrac{12}{60} x 100 = 20%

∴ Carbon in Urea is 20%